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<p>我的问题的目的是阅读这样一篇帖子:</p>
<pre><code>([
{
'title': 'Invade Manhatten, anyone?',
'tags': ['world-domination', 'hangout'],
'posts': [
{
'author': 'Mr. Sinister',
'content': "I'm thinking 9 pm?",
'upvotes': 2,
},
{
'author': 'Mystique',
'content': "Sounds fun!",
'upvotes': 0,
},
{
'author': 'Magneto',
'content': "I'm in!",
'upvotes': 0,
},
],
}
</code></pre>
<p>]))</p>
<p>并创建一个定义来输出:</p>
<pre><code>[('Mr. Sinister', '2', 'Cautioiusly Evil'), ('Magneto', '0', 'Insignificantly Evil'), ('Mystique', '0', 'Insignificantly Evil')]
</code></pre>
<p>其中列表按最高投票数到最低投票数排序,并按字母顺序断开连接。你知道吗</p>
<p>然而,当我看到这条线索时:</p>
<pre><code>([
{
'title': 'Invade Manhatten, anyone?',
'tags': ['world-domination', 'hangout'],
'posts': [
{
'author': 'Mr. Sinister',
'content': "I'm thinking 9 pm?",
'upvotes': 2,
},
{
'author': 'Mr. Sinister',
'content': "Sounds fun!",
'upvotes': 0,
},
{
'author': 'Mr. Sinister',
'content': "I'm in!",
'upvotes': 0,
},
],
}
</code></pre>
<p>]))</p>
<p>在作者多次发布的地方,我的程序输出:</p>
<pre><code>[('Mr. Sinister', '2', 'Cautioiusly Evil'), ('Mr. Sinister', '0', 'Insignificantly Evil'), ('Mr. Sinister', '0', 'Insignificantly Evil')]
</code></pre>
<p>我的程序打印每个帖子,而不是像这样组合结果:</p>
<pre><code>[('Mr. Sinister', 2, 'Cautiously Evil')]
</code></pre>
<p>只是澄清一下,如果线索是:</p>
<pre><code>([
{
'title': 'Invade Manhatten, anyone?',
'tags': ['world-domination', 'hangout'],
'posts': [
{
'author': 'Mr. Sinister',
'content': "I'm thinking 9 pm?",
'upvotes': 2,
},
{
'author': 'Loki',
'content': "Sounds fun!",
'upvotes': 2,
},
{
'author': 'Mr. Sinister',
'content': "I'm in!",
'upvotes': 2,
},
{
'author': 'Loki',
'content': "I'm in it!",
'upvotes': 20,
},
],
}
</code></pre>
<p>]))</p>
<p>它应该输入:</p>
<pre><code>[('Loki', 22, 'Justifiably Evil'), ('Mr. Sinister', 4, 'Cautiously Evil')]
</code></pre>
<p>我的代码如下:</p>
<pre><code> def author_rankings(thread_list):
# TODO: Determine (author, upvotes, ranking) over all threads.
counterA = 0
counterB=2
listA = []
Final = []
Double = {}
for i in thread_list[0]['posts']:
for ii in i:
if ii == 'content':
null = 1
else:
b = str(i[ii])
if b in Double:
Double[b]
a = b
if a.isdigit():
a = int(a)
listA.append(a)
bel=[]
for qq in listA:
if counterA == counterB:
bel = []
counterB+=2
if counterA%2 ==0:
bel.append(qq)
counterA+=1
else:
bel.append(qq)
qq = int(qq)
if qq == 0:
bel.append('Insignificantly Evil')
elif qq < 20:
bel.append('Cautiously Evil')
elif qq < 100:
bel.append('Justifiably Evil')
elif qq < 500:
bel.append('Wickedly Evil')
elif qq >= 500:
bel.append('Diabolically Evil')
counterA+=1
tuuple = tuple(bel)
Final.append(tuuple)
Final.sort()
Final.sort(key=lambda tup: -tup[1])
</code></pre>
<p>我知道我的代码有点不太懂/难读。很抱歉给您带来不便。你知道吗</p>
<p>谢谢你!你知道吗</p>