擅长:python、mysql、java
<p>创建列表时,会立即用字符串替换它。
尝试:</p>
<pre><code>if fn in firsts:
firsts[fn].append(full)
else:
firsts[fn] = [full]
</code></pre>
<p>而不是</p>
<pre><code>if fn in firsts:
firsts[fn].append(full)
else:
firsts[fn] = []
firsts[fn] = full
</code></pre>