擅长:python、mysql、java
<p>考虑到最后一个嵌套项始终是iterable(与内部项的总数无关)</p>
<pre><code>k_list = [(1,2,3,['a','b','c']), (4,5,6,['d','e','f']), (7,8,9,['g','h','i'])]
res = [list(i[:-1]) + i[-1] for i in k_list]
print(res)
</code></pre>
<p>输出:</p>
<pre><code>[[1, 2, 3, 'a', 'b', 'c'], [4, 5, 6, 'd', 'e', 'f'], [7, 8, 9, 'g', 'h', 'i']]
</code></pre>