擅长:python、mysql、java
<p>我想这应该仍然适用于优化的范围。你知道吗</p>
<pre><code>s = 'phhp'
def validate():
for i in range(len(s)):
if len(s[i:i+2]) != 2:
break
if 'ph' == s[i:i+2]:
if 'hp' in s[0:i] or 'hp' in s[i+2:i+4]:
return True
return False
print ('Found' if validate() else 'Not Found')
</code></pre>