java字母计数应用程序
package jdaprogrammingactivity22;
/*
*@Title: JDAProgrammingAssignment4
*@Description: Create a program the will count and display a table
* showing occurrence of each letter in the inputted word/phrase/sentence.
* The letters should be sorted in alphabetical order
*
* @author Jan Dierekh B. Arroyo
* Date: Created: July 28, 2019
*
*/
import java.util.*;
import static java.lang.System.*;
public class JDAProgrammingActivity22 {
static void header()
{
String s = "LETTER COUNTING APPLICATION";
out.println(s);
for(int i = 0; i < s.length(); i++)
{
out.print("-");
}
out.println();
}
static void input()
{
Scanner scan = new Scanner(System.in);
out.print("Enter a word/phrase/sentence: ");
String str1 = scan.nextLine();
toUpCase(str1);
out.println(">> Unique Letters:");
String sort = sortStr(str1);
out.println("Sorted String: " + sort);
uniqueLetter(sort);
}
static String sortStr(String str1)
{
char tempArray[] = str1.toCharArray();
Arrays.sort(tempArray);
return new String(tempArray);
}
static void toUpCase(String str1)
{
str1 = str1.toUpperCase();
out.println(">> Word/Phrase/Sentence: ");
out.println("\t" + str1 + "\n");
}
static void uniqueLetter(String str1)
{
int num = 0,COUNT = 0;
String line = "\t+-----+--------+-------+";
out.println(line);
out.println("\t| NO. | LETTER | COUNT | ");
out.println(line);
String[] words = str1.split("\\s+");
for (String word : words) {
out.println("\t| " + num + " |" + word + " | " + COUNT + " | ");
}
}
public static void main(String[] args) {
header();
input();
}
}
我正在制作一个程序,它将计数并显示一个表格,显示输入的单词/短语/句子中每个字母的出现情况。这些字母应该按字母顺序排列
我已经对字符串进行了排序,并将其更改为大写,因为这是必需的,而且我已经有了一个字符串出现的计数算法
我的问题在于期望的输出,你可以看看预期的结果。我不知道如何把它输出到一个表上,并把字符。请帮忙
我已经尝试使用switch检查每个字符,但我不知道如何使用switch检查字符串中的字符
int num,count;
char letter;
String line = "\t+-----+--------+-------+";
out.println(line);
out.println("\t| NO. | LETTER | COUNT | ");
out.println(line);
for(int i = 0; i >= str1.length(); i++)
{
out.println("\t| " + num + " |" + LETTER + " | " + COUNT + " | ");
}
# 1 楼答案
用地图记录你的信件和计数。如果使用
TreeMap
,默认情况下它将按键排序。因此,之前不需要对字符进行排序