java ArrayList字符串到int排序顺序

Question

我需要验证“升序排序顺序”选项卡是否正常工作。 但当我比较结果时，由于一位数和两位数的原因，它不起作用。 如何将ArrayList转换为int？这样行吗

        ArrayList<String> obtainedList = new ArrayList<>();
    List<WebElement> elementList = driver.findElements(By.xpath("//mat-table//mat-row/mat-cell[2]"));
    for (WebElement we : elementList) {
        obtainedList.add(we.getText());
    }
    // This is where I should convert array to int ?

    ArrayList<String> sortedList = new ArrayList<>();
    for (String s : obtainedList) {
        sortedList.add(s);
    }

    Collections.reverse(sortedList);
    Collections.sort(sortedList);

    Reporter.log(AddRule + obtainedList + sortedList + " Cloumn is display in  Ascending order");
    Add_Log.info(AddRule + obtainedList + sortedList + " Cloumn is display in  Ascending order");
    List<String> labels = elementList.stream().map(WebElement::getText).collect(Collectors.toList());
    SortedSet<String> sorted = new TreeSet<>(labels);
    assertThat(labels, contains(sorted));

    Assert.assertTrue(sortedList.equals(obtainedList));

输出

编号[5,7,8,10,11,12,19,22,92,96,98,99][10,11,12,19,22,5,7,8,92,96,98,99]列按升序显示

由于一位数和两位数的数字，排序不起作用。 如果我把字符串数组转换成int，那行吗？如何修复此代码

Answer 1

当然，如果您将obtainedList转换为List<Integer>，它将起作用

List<Integer> obtainedList = new ArrayList<>();

for(int i = 0; i < 10; i ++) {
    obtainedList.add(RandomUtils.nextInt(100));
}

Collections.reverse(obtainedList);
Collections.sort(obtainedList);

System.out.print(obtainedList);

Answer 2

您可以通过stream#map和stream#sorted从List<String>投影到List<Integer>对元素进行排序，然后最终收集到列表中

List<Integer> result = obtainedList.stream()
                                   .map(Integer::valueOf)
                                   .sorted() // sort the elements
                                   .collect(Collectors.toList());

或典型的for循环：

List<Integer> sortedList = new ArrayList<>();
for (String s : obtainedList) 
        sortedList.add(Integer.valueOf(s));
Collections.sort(sortedList); //sort the list after accumulating all the elements