java数学。随机if语句错误

Question

    int Comproll1= (int) (Math.random()*6+1);
    int Comproll2= (int) (Math.random()*6+1);
      while (m==1)
    { 
        {
        if (Comproll1==1 || Comproll2==1)
        {
            System.out.println("One of the computer's dice rolls was a 1, it lost all the points for the round & it is now your turn!");
            cr= cr-cr;
            m++;
        }
        else if (Comproll1==1 && Comproll2==1)
        {
            System.out.println("The Computer rolled 2 1's, their total number of points is now 0 & it is now your turn!");
            cp=cp-cp;
            m++;
        }
        else 
        {
            cr= Comproll1+Comproll2;
            cp= cp+cr;
        }
    }

大家好！上面是我的代码——不管出于什么原因，它总是会，不管发生什么，总是显示第一个选项，即“计算机的掷骰子中有一个是1，它在这一轮中失去了所有的点数……”。即使我改变了语句的顺序，它仍然会这样做。有人能给我解释一下为什么会这样吗？？谢谢

Answer 1

问题是，您需要先检查它们是否都是1，然后再检查它们是否都是1。如果我们看一下代码：

if (Comproll1==1 || Comproll2==1)
{
    System.out.println("One of the computer's dice rolls was a 1, it lost all the points for the round & it is now your turn!");
    cr= cr-cr;
    m++;
}
else if (Comproll1==1 && Comproll2==1)
{
    System.out.println("The Computer rolled 2 1's, their total number of points is now 0 & it is now your turn!");
    cp=cp-cp;
    m++;
}

如果：

Comproll1=1

Comproll2=1

您希望它将进入else if (Comproll1==1 && Comproll2==1)但是，如果这是真的，那么if (Comproll1==1 || Comproll2==1)将始终是真的

要解决此问题，只需更改if的顺序，如下所示：

if (Comproll1==1 && Comproll2==1)
{
    System.out.println("The Computer rolled 2 1's, their total number of points is now 0 & it is now your turn!");
    cp=cp-cp;
    m++;
}
else if (Comproll1==1 || Comproll2==1)
{
    System.out.println("One of the computer's dice rolls was a 1, it lost all the points for the round & it is now your turn!");
    cr= cr-cr;
    m++;
}

希望这有帮助：）

（你还需要重新掷骰子（正如艾略特·弗里希在回答中所说的那样））

Answer 2

尝试更改if语句的顺序。从逻辑上讲，如果两个比较中的一个为真，则将执行第一条语句。在第二个条件else if (Comproll1==1 && Comproll2==1)为真的情况下，第一个条件if (Comproll1==1 || Comproll2==1)也将为真

由于您已经以if-else-if方式链接了if语句，因此将执行第一个等同于true的if语句

    if (Comproll1==1 && Comproll2==1)
    {
        System.out.println("The Computer rolled 2 1's, their total number of points is now 0 & it is now your turn!");
        cp=cp-cp;
        m++;
    }
    else if (Comproll1==1 || Comproll2==1)
    {
        System.out.println("One of the computer's dice rolls was a 1, it lost all the points for the round & it is now your turn!");
        cr= cr-cr;
        m++;
    }
    else 
    {
        cr= Comproll1+Comproll2;
        cp= cp+cr;
    }

Answer 3

据我所知，因为你没有滚动

int Comproll1= (int) (Math.random()*6+1);
int Comproll2= (int) (Math.random()*6+1);
while (m==1)
{

应该是

while (m==1)
{
  int Comproll1= (int) (Math.random()*6+1);
  int Comproll2= (int) (Math.random()*6+1);

此外，Java命名约定是变量的驼峰大小写（以小写字母开头）。所以，Comproll1可能是compRoll1。最后，我个人更喜欢^{}和6面骰子，可能看起来像

Random rand = new Random();
while (m==1)
{
  int compRoll1 = rand.nextInt(6) + 1;
  int compRoll2 = rand.nextInt(6) + 1;

编辑实际上，您还需要颠倒测试顺序。因为如果其中一个是真的，那么就永远不可能输入两个都是真的测试

if (Comproll1==1 || Comproll2==1) {
  // Here.
}else if (Comproll1==1 && Comproll2==1) {
  // Will never enter here.
}

将命令切换到

if (Comproll1==1 && Comproll2==1) {
  // Both.
}else if (Comproll1==1 || Comproll2==1) {
  // Either.
}