java Play Framework：将服务器的响应解析为Xml返回空文档

Question

我有一个Play web应用程序，可以向服务器发出HTTP请求

请求进行得很顺利：我得到了一个200状态码和Content type=“application/xml”的响应

如果我打印到stdout响应体，我会看到一个格式良好的Xml文档

然而，如果我试图创建一个组织。w3c。多姆。来自响应的XML文档 使用WSResponse。asXml（），该方法返回一个空文档

以下是我的代码的相关部分：

private WSResponse sendPostRequest(String url, String body) {

    WSRequest request = WS.url(url);

    request.setHeader("Content-type", "application/x-www-form-urlencoded");

    return request.post(body).get(5000L);
}

以及：

public Result requestDefaultImport() {

    String url = "some_url";
    String body = "some_body";

    WSResponse response = sendPostRequest(url, body);

    System.out.println(response.getBody()); //prints well-formed Xml

    Document xmld = response.asXml(); 
    System.out.println(xmld); //prints: #[null document]


    return ok();
}

我做错了什么

Answer 1

据我所知，你正在打印字符串

System.out.println(response.getBody());

但是，您正在打印一个组织。w3c。多姆。文件位于

 System.out.println(xmld);

有关将文档转换为字符串的解决方案，请访问

How do I convert a org.w3c.dom.Document object to a String?

Answer 2

请尝试以下代码：

Document doc = request().body().asXml();
Source source = new DOMSource(doc);
StringWriter stringWriter = new StringWriter();
StreamResult result = new StreamResult(stringWriter);
TransformerFactory factory = TransformerFactory.newInstance();
javax.xml.transform.Transformer transformer = factory.newTransformer();
transformer.transform(source, result);
String xmlStr = stringWriter.getBuffer().toString();
System.out.println(xmlStr);

或者，如果从肥皂中消费：

Document doc = soapBody.extractContentAsDocument();
Source source = new DOMSource(doc);
StringWriter stringWriter = new StringWriter();
Result result = new StreamResult(stringWriter);
TransformerFactory factory = TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer();
transformer.transform(source, result);
strSoapBody = stringWriter.getBuffer().toString();