从SQLite for java/安卓中的数据库表中删除除前n之外的所有内容

Question

我是java新手，但我正在尝试编写代码：

      SQLiteDatabase db = this.getWritableDatabase();
        //db.execSQL("delete from " + TABLE_BOOKMARKS + " where " + KEY_ID + "  not in (select " + KEY_ID + " from " + TABLE_BOOKMARKS + " order by " + KEY_ID + " limit 10)" );
        //db.execSQL("DELETE FROM " + TABLE_BOOKMARKS + " WHERE " + KEY_ID + " NOT IN (SELECT TOP 10 " + KEY_ID + " FROM " + TABLE_BOOKMARKS + ")" );

        db.execSQL("Delete From "+TABLE_BOOKMARKS+"  where "+ KEY_ID  + " not in (Select Top 10 "+ KEY_ID +" from "+ TABLE_BOOKMARKS + " order by " + KEY_ID +")");
        db.close(); // Closing database connection

你可以在代码中看到，我尝试了三种不同的方法，但当我运行它时，我的应用程序返回错误并停止

我犯了这个错误：

安卓.database.sqlite.SQLiteException: near "10": syntax error: , while compiling: Delete From bookmarks where id not in (Select Top 10 id from bookmarks order by id)

Answer 1

你可以试试

db.execSQL("Delete From "+TABLE_BOOKMARKS+"  where "+ KEY_ID  + " not in (Select "+ KEY_ID +" from "+ TABLE_BOOKMARKS + " order by " + KEY_ID +" limit 10)");